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x^2-12x+14.36=0
a = 1; b = -12; c = +14.36;
Δ = b2-4ac
Δ = -122-4·1·14.36
Δ = 86.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-\sqrt{86.56}}{2*1}=\frac{12-\sqrt{86.56}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+\sqrt{86.56}}{2*1}=\frac{12+\sqrt{86.56}}{2} $
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